Helaine graphed the equation 12x – 4y = 3. What was the slope of Helaine’s line?\",[{""content"":""<p><strong>Answer:<\/strong><\/p><p>[tex]\\large\\boxed{\\text{The slope}\\ m=3}[\/tex]<\/p><p><strong>Step-by-step explanation:<\/strong><\/p><p>The slope-intercept form of an equation of a line:<\/p><p>[tex]y=mx+b[\/tex]<\/p><p>m - slope<\/p><p>b - y-intercept<\/p><p>We have the equation of a line in the standard form:<\/p><p>[tex]12x-4y=3[\/tex]<\/p><p>Convert to the slope-intercept form:<\/p><p>[tex]12x-4y=3[\/tex] \u00a0 \u00a0 \u00a0 \u00a0 <em>subtract 12x from both sides<\/em><\/p><p>[tex]-4y=-12x+3[\/tex] \u00a0 \u00a0 \u00a0 \u00a0<em>divide both sides by (-4)<\/em><\/p><p>[tex]y=\\dfrac{-12}{-4}x+\\dfrac{3}{-4}\\\\\\\\y=3x-\\dfrac{3}{4}[\/tex]<\/p>""}